The autorickshaw fare in a city is as follows: For the first kilometre,the fare is ₹ $10$,and for the subsequent distance,it is ₹ $3$ per $km$. Taking the distance covered as $x$ $km$ and the total fare as ₹ $y$,write a linear equation for this information and draw its graph. Find the total fare for a journey of $4$ kilometres from the graph.

(D) Let the total distance covered be $x$ $km$ and the total fare be ₹ $y$.
For the first $1$ $km$,the fare is ₹ $10$.
For the remaining distance $(x - 1)$ $km$,the fare is $3(x - 1)$.
Therefore,the total fare $y = 10 + 3(x - 1)$.
Simplifying the equation: $y = 10 + 3x - 3$,which gives $y = 3x + 7$.
To draw the graph,we find points:
If $x = 1, y = 10$.
If $x = 2, y = 13$.
If $x = 3, y = 16$.
Plotting these points on a graph and joining them gives a straight line.
For a journey of $4$ $km$,substitute $x = 4$ in the equation: $y = 3(4) + 7 = 12 + 7 = 19$.
Thus,the total fare for $4$ $km$ is ₹ $19$.